Math, asked by shrivastava082324, 10 months ago

if a+b+c=12,A^[2]+b^[2]+c^[2]=50,then ab+bc+ca=?

Answers

Answered by TejusPal
1

Answer:

47

Step-by-step explanation:

(a+b+c)^2=a^2+b^2+c^2 +2(ab+bc+ca)

ab+bc+ca=47

Answered by itzkarina
1

(a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ca (formula)

(a+b+c)^2 = a^2 + b^2+ c^2 + 2(ab+bc+ca)

12^2 = 50 + 2(ab+bc+ca) (Substituting the given values)

144 = 50 + 2(ab+bc+ ca)

144 - 50 = 2(ab+bc+ca)

94 = 2(ab+bc+ ca)

94/2 = ab+bc+ca

47 = ab+ bc+ ca

Hope it helps!

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