if a+b+c= 12 and a^2+b^2+c^2=100 find the value of ab+bc+ca
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The answer will be 22.
Step-by-step explanation:
Given,
a+b+c= 12; (i)
a^2+b^2+c^2=100; (ii)
Square both side in eq. (i);
(a+b+c)^2 = (12)^2;
a^2+b^2+c^2 + 2ab+2bc+2ca = 144; (since, (a+b+c)^2 = a^2+b^2+c^2 + 2ab+2bc+2ca)
100 + 2ab+2bc+2ca = 144; (from eq. (ii))
2ab+2bc+2ca = 44;
2(ab+bc+ca) = 44;
ab+bc+ca = 22;
That's all.
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