Math, asked by parzival2005, 10 months ago

if a+b+c=12 and a^2+b^2+c^2=24 find the value of ab+bc+ca ​

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Answered by sweetyrani99912
1

Answer:

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Answered by QuickSilver04
2

\huge{\mathcal{\green{Answer}}}

(a + b + c) {}^{2}  = a {}^{2}  + b {}^{2}  + c {}^{2}  + 2ab + 2bc + 2ca \\ (12) {}^{2}  = 24 + 2(ab + bc + ca) \\ 144 = 24 + 2(ab + bc + ca) \\ 144 - 24 = 2(ab + bc + ca) \\ 120 = 2(ab + bc + ca) \\  \frac{120}{2}  = (ab + bc + ca)

\huge{\mathcal{\orange{\boxed{(ab+bc+ca)=60}}}}

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