Question

if a+b+c=12 and a^2+b^2+c^2. =64 then find value of ab+bc +ac​

Answer 1

Answer:

since we know that :-

(a+b+c)^2 = (a^2+b^2+c^2)+2(ab+bc+ca)

now according to question :-

12^2 = (64)+2(ab+bc+ca)

144-64 = 2(ab+bc+ca )

80 = 2(ab+bc+ca)

80/2 = ab+bc+ca

40 = ab + bc + ac

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Answer 2

Answer:

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

(12)^2=64+2(ab+bc+ca)

144=64+2(ab+bc+ca)

144-64=2(ab+bc+ca)

80=2(ab+bc+ca)

80/2=ab+bc+ca

40=ab+bc+ca

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