if a+b+c=12 and a×a+b×b+c×c=64 find ab +bc+ac
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here is ur answer mate.....
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Given,
a + b + c = 12
a² + b² + c² = 64
ab + bc + ca = ?
===========================
a + b + c = 12
square on both sides,
(a + b + c)² = (12)²
=================
By Formula,
=================
(a + b + c)² = (12)²
a² + b² + c² + 2(ab + bc + ca) = 144
Putting the given values,
64 + 2(ab + bc + ca) = 144
2(ab + bc + ca) = 144 - 64
2(ab + bc + ca) = 80
ab + bc + ca = 80/2
ab + bc + ca = 40
i hope this will help you
-by ABHAY
a + b + c = 12
a² + b² + c² = 64
ab + bc + ca = ?
===========================
a + b + c = 12
square on both sides,
(a + b + c)² = (12)²
=================
By Formula,
=================
(a + b + c)² = (12)²
a² + b² + c² + 2(ab + bc + ca) = 144
Putting the given values,
64 + 2(ab + bc + ca) = 144
2(ab + bc + ca) = 144 - 64
2(ab + bc + ca) = 80
ab + bc + ca = 80/2
ab + bc + ca = 40
i hope this will help you
-by ABHAY
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