Question

If a+b+c= 12 and a²+b²+c²= 100, Find ab+bc+ca. ​

Answer 1

Answer:

(a+b+c) ^2 = 144

a^2 + b^2 +c^ 2 + 2ab + 2bc +2 ca =144

100 + 2ab+2ac+2bc =144

2ab+2ac+2bc = 44

ab+bc+ca =22

Answer 2

Answer:

HI BUDDY HERE IS ANSWER!!!!!

IF a+b+c=12

then,

(a+b+c)^2 = a^2+b^2+c^2+2(ab+bc+ca)

as putting the value we get

100+2(ab+bc+ca) = 0

(ab+bc+ca) = -100/2

=. (-50)