Math, asked by SanjanaShetty06, 9 months ago

If a +b+c =12
and a² +b²+ c² = 50, find ab + bc + ca.

please guys, it's urgent, I hv test right now, help me to solve it

Answers

Answered by hritiksingh1

Answer:

${(a + b + c)}^{2} = {a}^{2} + {b }^{2} + {c}^{2} + 2ab + 2bc + 2ca$

${12}^{2} = 50 + 2ab + 2bc + 2ca$

144=50+2(ab+bc+ca)

94=2(ab+bc+ca)

47=ab+bc+ca

here is your answer

hope this help you

Answered by silentloffer

$\Huge{\bold{\mathrm{\underline{\red{ANSWER}}}}}$

you know that...

$(a + b + c) {}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca$

$hear...(a + b + c) = 12$

$and... \: \: ({a}^{2} + {b}^{2} + {c}^{2} ) = 50$

${12}^{2} = 50 +2 ab + 2bc + 2ca$

$144 - 50 = 2(ab + bc + ca)$

$94 = 2(ab + bc + ca)$

then...

$ab + bc + ca = \frac{94}{2}$

$ab + bc + ca = 47 \: \: ans...$

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If a +b+c =12and a² +b²+ c² = 50, find ab + bc + ca.please guys, it's urgent, I hv test right now, help me to solve it​

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If a +b+c =12
and a² +b²+ c² = 50, find ab + bc + ca.

please guys, it's urgent, I hv test right now, help me to solve it