if a+b+c=12 and a² + b²+ c²= 50, find ab+
bc+ ca
Select from the Answers below
O 97 0 62
O 47 O 38
Answers
Answered by
2
Answer:
94
None of the answer is right check the options again
hope it helps you
Attachments:
Answered by
51
Analysis→
Here we're given that a+b+c=12 and a²+b²+c²=50. And we've to find the value of ab+bc+ca. And according to the Identity: (x+y+z)²=x²+y²+z²+2(xy+yz+zx) And by substituting the variables and putting the values given, we can easy find the answer.
Options Given→
- 97
- 47
- 62
- 38
Given→
- a+b+c=12
- a²+b²+c²=50
To Find→
The value of ab+bc+ca.
Answer→
☞ Hence the value of ab+bc+ca is 47, therefore option (2) is the correct answer.
Know More→
Some more algebraic identities:-
- (x+y)²=x²+y²+2xy
- (x-y)²=x²+y²-2xy
- x²-y²=(x+y)(x-y)
- (x+a)(x+b)=x²+x(a+b)+ab
- (x+b)³=x³+y³+3xy(x+y)
- (x-y)³=x³-y³-3xy(x-y)
- x³+y³=(x+y)(x²+y²-xy)
- x³-y³=(x-y)(x²+y²+xy)
- x³+y³+z³-3xyz=(x+y+z)(x²+y²+z²-xy-yz-zx)
HOPE IT HELPS.
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