Question

If a+b+c=12 and a²+b²+c²=64, find the value of ab+bc+ac

Answer 1

______________________________________________________________________________________________________________________________________________________________________________

here is your answer

given that , a+b+c= 12, a²+b²+c²= 64

you need to find ab + bc + ca

(a+b+c)² = a²+b²+c²+ 2 ab + 2bc + 2ca

(12)² = 64 + 2(ab+bc+ca)

144-66 = ( ab + bc + ca)

144-66 = ab + bc + ca

80/2 = ab + bc + ca

ab +bc + ca = 40

______________________________________________________________________________________________________________________________________________________________________________

hope this helps u

pls mark as brainliest

Answer 2

Given
a+b+c=12. and a²+b²+c²=64
We know that
(a+b+c)sq.=a²+b²+c²+2(ab+bc+ca)
So,
( 12)sq.= 64+2×(ab+bc+ca)

144=64+2×(ab+bc+ca)

2(ab+bc+ca) =144-64

2(ab+bc+ca)= 80

ab+bc+ca=80/2

ab+bc+ca =40

Hope you understand and helpful.