If (a+b+c)=12 and a2+b2+c2=64,find the value of (ab+bc+ca)
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Answer:
40
Step-by-step explanation:
as , (a+b+c)^2= a2+b2+c2+2ab+2bc+2ac
and a+b+c=12
therefore, (12)^2=144
so, 144=a2+b2+c2+2ab+2bc+2ac
and a2+b2+c2=64
therefore, 144=64+2ab+2bc+2ac
so, 80=2(ab+bc+ac)
therefore, ab+bc+ac=40
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