If
A+b+C = 12 and a² +b² + c²=64
then find the value of (ab +bc + CA)
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Answered by
2
40
Step-by-step explanation:
we know that (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
hare (a+b+c)=12 so,(a+b+c)^2=12^2=144
given a^2+b^2+c^2=64 so 2(ab+bc+ca)=144-64=80
so, (ab+bc+ca)=40
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