If a+b+c =12 and a2 +b2 +c2 =66 then find the value of ab+bc + ac
Answers
Answered by
83
we have/ a+b+c =12 .a2 +b2 +c2 =66
(a+b+c+)² = a²+b +c² +2(ab+bc+ca)
(12)² = 66 + 2(ab +bc+ca
144 = 66 + 2(ab+nc+ca)
144-66 = 2(ab+bc+ca)
78 = 2(ab+bc+ca)
∴ab+bc+ca = 78/2
= 39
(a+b+c+)² = a²+b +c² +2(ab+bc+ca)
(12)² = 66 + 2(ab +bc+ca
144 = 66 + 2(ab+nc+ca)
144-66 = 2(ab+bc+ca)
78 = 2(ab+bc+ca)
∴ab+bc+ca = 78/2
= 39
Answered by
13
Step-by-step explanation:
Ur answer is attached here.
Hope it helps u
Plz mark me as brainliest
Attachments:
Similar questions