if a+b+c=12 and ab+bc+ca=22 find a2+b2+c2
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Given,
(a+b+c) = 12
(ab+bc+ca) = 22
Using Identity,
(a+b+c)² = (a²+b²+c²) + (ab+bc+ca)
= (12)² = (a²+b²+c²) + (22)
= 144 = (a²+b²+c²) + 22
= 122 = a²+b²+c²
The Value is 122.
I hope this helps.
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