Math, asked by adityakumar990362171, 1 month ago

if a+b+c=12 and ab+bc+ca=22 find a2+b2+c2

Answers

Answered by dipamcool2016
0

Given,

(a+b+c) = 12

(ab+bc+ca) = 22

Using Identity,

(a+b+c)² = (a²+b²+c²) + (ab+bc+ca)

= (12)² = (a²+b²+c²) + (22)

= 144 = (a²+b²+c²) + 22

= 122 = a²+b²+c²

The Value is 122.

I hope this helps.

Similar questions