If a + b + c = 12 and ab + bc + ca = 22, find a2
+ b2
+ c2
using identities
Answers
Answered by
2
Answer:
100
Step-by-step explanation:
a+b+c=12
square on both sides
(a+b+c)^2=(12)^2
a^2+b^2+c^2+2ab+2bc-2ca=144
a^2+b^2+c^2+2(ab+bc+ca)=144
now,
a^2+b^2+c^2+2(22)=144
a^2+b^2+c^2=144-44
a^2+b^2+c^2=100
Similar questions