Math, asked by Manshi7505, 1 year ago

If A+B+C=13,A2+B2+C2=29,Find Ab+Bc+Ca

Answers

Answered by ItsMeKing
0

Answer:

70

Step-by-step explanation:

(A+B+C)^2 = A^2 + B^2 + C^2 + 2AB + 2BC + 2CA

Putting the values in above mentioned identity:

13^2 = 29 +2(AB + BC + CA)

169 = 29 + 2(AB + BC + CA)

169-29 = 2(AB + BC + CA)

140 = 2(AB + BC + CA)

140/2 = AB + BC + CA

Therefore, AB + BC + CA = 70

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