If A+B+C= 13 AND A^2+B^2+C^2=69
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Answer:
Step-by-step explanation:
a+b+c=13
squaring on both sides
(a+b+c)^2=13^2
a^2+b^2+c^2+2ab+2bc+2ca=169
69+2ab+2bc+2ca=169
2(bc+ca+ab)=169-69
bc+ca+ab=100/2=50
Answered by
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.....Hey mate refer the above attachment....
...U can understand easily....
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