Question

If a+b+c=13 and ab+bc+ca= 6, find the value of a² +b² +c²
please answer it's urgent​

Answer 1

Step-by-step explanation:

a+b+c=13

squaring on both sides

(a+b+c)²=13²

a²+b²+c²+ab+bc+ca=169

a²+b²+c²+(ab+bc+ca)=169

a²+b²+c²+6=169

a²+b²+c²=169-6

a²+b²+c²=163

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