Question

IF
A+B+C=13
C+D+E=13
E+F+G=13
G+H+I=13
Then the value of E ?; IF; A+B+C=13; C+D+E=13; E+F+G=13; G+H+I=13; Then the value of E ?

Answer 1

It's a type of mathematical riddle in which you have to predict the value of different letters,

The secret lies in taking up the value of just the last letter from the previous equation,

Well,

It's hit or miss type of situation,

I have tried many ways,

I end up on,

A + B + C = 13 = 6 + 5 + 2

Where,

A = 6

B = 5

C = 2

Then,

C + D + E = 13 = 2 + 7 + 4

Where,

C = 2,

D = 7,

E = 4

Again,

E + F + G = 13 = 4 + 8 +1

Where,

E = 4

F = 8

G = 1

And,

G + H + I = 13 = 1 + 3 + 9

Where,

G = 1

H = 3

I = 9

So, from above ⤴ we can clearly observe the value of E = 4.

Answer 2

A+B+C=13

C+D+E=13

E+F+G=13

G+H+I=13

Here A to I are 1 to 9 distinct numbers

lets add all 4 equations

A+B+C+C+D+E+E+F+G+G+H+I=13+13+13+13

=>A+B+C+D+E+F+G+H+I +C+E+G = 52

A to I are 1to 9

so sum of first 9 natural numbers

= (9/2)(9+1) = 45

=> 45 + C+E+G = 52

=> C+E+G = 7

7 can be obtained by

1 + 2 + 4

now

C+D+E=13

E+F+G=13

C+E>3 as D<10

E+F>3 as F<10

Both the equation will satisfy in case of E = 4

so answer of the question= 4