If a+b+c=135,prove that(1+cotA)(1+cotB)=2
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Answered by
1
Answer:
Given A+B=135
∘
⟹cot(A+B)=cot135
∘
⟹
cotA+cotB
cotAcotB−1
=−1
⟹cotA+cotB+cotAcotB=+1
⟹cotA+cotB+cotAcotB+1=2
⟹cotA(1+cotB)+(1+cotB)=2
⟹(1+cotA)(1+cotB)=2
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Answered by
6
Appropriate Question :-
If A + B = 135°, prove that (1 + cotA) (1 + cotB) = 2
Given that,
So,
On adding 1 on both sides, we get
Hence,
Formulae Used :-
Additional information :-
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