if a+b+c=14,a²+b²+c²=100,then what is ab +bc+ca
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Given
- a + b + c = 14
- a² + b² + c² = 100
To find
- ab + bc + ca = ?
Solution
As we know that
→ (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
→ (a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
→ (14)² = 100 + 2(ab + bc + ca)
→ 196 - 100 = 2(ab + bc + ca)
→ 2(ab + bc + ca) = 96
→ ab + bc + ca = 96/2
→ ab + bc + ca = 48
Hence,
- ab + bc + ca = 48
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