Question

if a+b+c=14 , a²+b²+c²=74 ,
a³+b³+c³=424 then find the value of ABC!

Answer 1

a^3 + b^3 + c^3 -3abc

= a+b+c(a^2 +b^2+c^2 -ab -bc-ca)

14(74 -ab -bc-ca)

solve by id (a+b+c)^2

get value of ab -bc-ca

keep = a^3 + b^3 + c^3 -3abc

a^3 + b^3 + c^3 put its value

u will get abc