Question

If (a + b + c) = 14 and (a² + b² + c²) = 74, find the value of (ab + bc + ca).
kindly don't spam​

Answer 1

Step-by-step explanation:

We have

(a+b+c)² = a²+b²+c² + 2(ab+bc+ca)

=> (14)² = 74+2(ab+bc+ca)

=> 2(ab+bc+ca) = 196-74

$ab + bc + ca = \frac{196 - 74}{2} = 122$

=> ab+bc+ca = 61

Answer 2

Answer:

We have

(a+b+c)² = a²+b²+c² + 2(ab+bc+ca)

=> (14)² = 74+2(ab+bc+ca)

=> 2(ab+bc+ca) = 196-74

$ab+bc+ca= \frac{196 - 74}{2} = 122$

=> ab+bc+ca = 61

hope it's help you

mark me as brainlist