Question

If (a + b + c) = 14 and
(a² + b² +c²) = 74, find the value of (ab + bc + ca).​

Answer 1

Answer:

extract this from formula I hope you know

u will get

(a+b+c)^2 = a^2+b^2+c^2 +2(ab +BC+AC)

substituting values we get

61

Answer 2

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$(a + b + c) = 14 \\ (a {}^{2} + b {}^{2} + c {}^{2} ) = 74 \\ (ab + bc + ca) = ? \\ \\ = since \\ \\ \: \: (a + b + c) {}^{2} = a {}^{2} + b {}^{2} + c {}^{2} + 2(ab + bc + ca) \\ \\ = (14) {}^{2} = 74 + 2(ab + bc + ca) \\ \\ = 196 - 74 = 2(ab + bc + ca) \\ \\ ab + bc + ca = \frac{122}{2} = 61 \: \: \: answer..$

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