If a + b + c = 15 ab+bc+ a = 81 . Find the value of a ^ 2 + b ^ 2 + c ^ 2 = ?
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1
Answer:
13
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2
Answer:
(a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
∴ (15)² = 81 + 2(ab + bc + ca)
∴ 2(ab + bc + ca) = 225-81=144
ab + bc + ca = 144/2
⇒ ab + bc + ca = 72
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