Math, asked by adityadavps8f2021, 1 month ago

If a + b + c = 15 ab+bc+ a = 81 . Find the value of a ^ 2 + b ^ 2 + c ^ 2 = ?​

Answers

Answered by AlokBhandari
1

Answer:

13

Step-by-step explanation:

Answered by malaytrivedi12345
2

Answer:

(a + b + c)²  = a² + b² + c² + 2(ab + bc + ca)

∴ (15)² = 81 + 2(ab + bc + ca)

∴ 2(ab + bc + ca) = 225-81=144

ab + bc + ca =  144/2

⇒ ab + bc + ca = 72

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