if a+b+c=15 and ab+bc+ac=60then find the value of a^2+b^2+c^2?
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Answered by
3
Hey !
⭐Here is your answer ⭐!
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( a + b + c )2 = a2 + b2 + c2 + 2 ( ab + bc + ca )
=> [ 15 ]2 = a2 + b2 + c2 + 2 [ 60 ]
=> 225 = a2 + b2 + c2 + 120
=> a2 + b2 + c2 = 105
Hope it helps you !!
__________________________
__________________________
⭐Here is your answer ⭐!
_________________________
_________________________
( a + b + c )2 = a2 + b2 + c2 + 2 ( ab + bc + ca )
=> [ 15 ]2 = a2 + b2 + c2 + 2 [ 60 ]
=> 225 = a2 + b2 + c2 + 120
=> a2 + b2 + c2 = 105
Hope it helps you !!
__________________________
__________________________
Answered by
0
(a+b+c)²=a^2 + b^2 + c^2 + 2ab + 2bc + 2ca
(15)²=a²+b²+c²+2(ab+bc+ca)
225=a²+b²+c²+2(60)
225-120=a²+b²+c²
105=a²+b²+c²
(15)²=a²+b²+c²+2(ab+bc+ca)
225=a²+b²+c²+2(60)
225-120=a²+b²+c²
105=a²+b²+c²
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