If a + b + c = 15 and ab + bc + ca = 30, find a 2 + b 2 + c 2 .
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Answered by
0
Answer:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ac
= (15)²=a²+b²+c²+2(ab+bc+ac)
= 225=a²+b²+c²+2(30)
= 225=a²+b²+c²+60
= 225-60=a²+b²+c²
= 165=a²+b²+c²
Answered by
2
EXPLANATION.
=> a + b + c = 15
=> ab + bc + ca = 30
To find a² + b² + c².
according to the question,
As we know that,
Formula of ( a + b + c)²
( a + b + c)² = a² + b² + c² + 2 ( ab + bc
+ ca)
put the value in above equation
we get,
=> ( 15 )² = a² + b² + c² + 2 ( 30 )
=> 225 = a² + b² + c² + 60
=> 225 - 60 = a² + b² + c²
=> a² + b² + c² = 165
Therefore,
value of ( a² + b² + c² ) = 165
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