Math, asked by manvivats093, 8 months ago

If a+b+c=15 and ab+bc+ca=74. Find (a2+b2+c2).

Answers

Answered by Afjal1
4

Answer:

(a+b+c)^2= a2+b2+c2+ 2 (ab+bc++ca)

225 (15×15)÷ 148(2×74)= a2+b2+c2

a2+b2+c2= 225÷148=1.5

I hope it helps u

Answered by Anonymous
2

Refer to the attachment !

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