Question

If (a+b+c) = 15 and (ab + bc+ca) = 74. find the value of (a²+b²+c²)​

Answer 1

Answer:

Step by step explanation in attachment

Answer 2

Answer:

77

Step-by-step explanation:

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

15^2=a^2+b^2+c^22.74

225=a^2+b^2+c^2+148

225-148=a^2+c^2+c^2

77=a^2+b^2+c^2