Question

If a+b+c= 16 ,a²+b²+c²= 250 Find 1/3(ab+bc+ca) *​

Answer 1

Step-by-step explanation:

(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) => (a + b + c)2 = 250 + 2 x 3 = 250 + 6 = 256 => (a + b + c)2 = (± 16)2 => a + b + c = ± 16

ab+bc+ca=3

Answer 2

Answer:

answer is 1

Step-by-step explanation:

(a + b +c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca.

put values,

square of 16 = 250 + 2( ab +bc+ ca )

256 - 250 = 2 (ab+ bc+ca )

6/3*2 = 1/3 (ab +bc +ca )

1 = 1/3 ( ab+ bc+ ca )

hope this will be helpful