Question

if a+b+c=16 and ab+bc+ca=3 then find the value of a²+b²+c²​

Answer 1

Answer:

Given: a+b+c= 16... eq(1) and ab+bc+ca=3...eq(2)

squaring both sides of equation 1,

(a+b+c)^2=(16)^2

=> a^2+b^2+c^2+2(ab+bc+ca)= 256.

[ Since, (a+b+c)^2 = a^2+b^2+c^2+(2ab+bc+ca)]

=> a^2+b^2+c^2+(2×3)= 256 [ Using eq(2)]

=> a^2+b^2+c^2=256-6

=> a^2+b^2+c^2= 250

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