If A+B+C=180 & Sinc=1 then prove tanA.tanB=1
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Answered by
23
Sin C = 1, therefore C = 90'.
Now,
A+B+90 = 180
A+B = 90
A = 90-B ---(1)
tan A x tan B = 1
tan (90-B) x tan B = 1
cot B x tan B = 1
Hence, proved.
Now,
A+B+90 = 180
A+B = 90
A = 90-B ---(1)
tan A x tan B = 1
tan (90-B) x tan B = 1
cot B x tan B = 1
Hence, proved.
Answered by
2
Answer:
if sinc=1 then c=90'
Step-by-step explanation:
A+B+C=180
THEN A+B=90. (C=90)
A=90-B
tanA =tan(90-B)
now l. h. s = tanA. tanb
= tan(90-B) . tanB
= cotB. tanB
= 1. (proved)
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