If A+B+C= 180 then prove that ,
Cos 4A +Cos 4B +Cos 4C =-1+4Cos2A Cos 2B Cos 2C
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Step-by-step explanation:
A+B+C= 180
cos4A+cos4B+cos4c
cos4(A+B+C) =180
cos 4A +cos4B -sin 4(2a)
cos4-tan4c
1+4cos 2a+cos2b+cos2c
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