Question

If A + B + C = 1800, prove that

sin (B + C – A) + sin (C + A – B) + sin (A + B – C) = 4 sin A sin B sin C.

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Answer 1

Answer:

We have

A+ B+ C = 180°

sin (B + C – A) + sin (C + A – B) + sin (A + B – C) = 4 sin A sin B sin C

So consider LHS = sin (B + C – A) + sin (C + A – B) + sin (A + B – C)

= sin (π– A – A) + sin (π – B – B) + sin (π– C – C)(since A + B + C = π)

= sin 2A + sin 2B + sin 2C

= 4 sin A sin B sin C

HOPE IT HELPS

Answer 2

Answer:

sin 2a 3b and 4ç

Step-by-step explanation:

15/√2 × 10–5