Question

If A +B+C=180°. then show that Sin(B+C) SinA

Answer 1

Answer:

Step-by-step explanation:

A+B+C = 180

=> B+C = 180 -A

Taking Sine on both sides.

Sin(B+C) = Sin(180 - A)

               = SinA           (∵Sin (180-θ) = SInθ)

                = R.H.S

Hence proved....