Question

if A+B+C=180°show that Tan2a+Tan2b+Tan2c=Tan2a tan2b tan2c​

Answer 1

Answer:

A + B + C = 180° ⇒ 2A + 2B + 2C = 360° 2A + 2B = 360° – 2C tan(2A + 2B) = tan(360° – 2C) tan2A+tan2B1−tan2A.tan2Btan2A+tan2B1−tan2A.tan2B = −tan2c1−tan2c1 tan2A + tan2B = – tan2C + tan2A tan2B tan2C tan2A + tan2B + tan2C = tan 2A tan2B · tan2CRead more on Sarthaks.com - https://www.sarthaks.com/643729/prove-that-tan2a-tan2b-tan2c-tan2a-tan2b-tan2c