Question

If a+b+c =2,ab+bc+ca=-1,abc=-2 then find the value of a^3+b^3+c^3

Answer 1

Answer:

8

Step-by-step explanation:

we know that (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

2^2=a^2+b^2+c^2+2(-1)

a^2+b^2+c^2=6

we know that a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

a^3+b^3+c^3-3abc=(2){6-(-1)}

a^3+b^3+c^3-3(-2)=14

a^3+b^3+c^3=8

hope it helps you