Question

IF a + b +c = 2 , ab +bc+ca =-1 and abc = -2 find the value of a 3 + b 3 + c3

Answer 1

Answer:

$a + b + 4 { {3}^{?} }^{2} = 0 = 33 {33 \frac{3 \frac{?}{?} }{?} }^{?} | = 2| \beta \gamma \beta \beta \pi$

Answer 2

Answer:

a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)

first we have to find the value a2+b2+c2

(a+b+c)2=a2+b2+c2+2ab+2bc+2ca

a2+b2+c2=(a+b+c)2-(2ab+2bc+2ca)

=4-2(1)

=2

a3+b2+c3-3(-2)=2*(2-(-1))

a3+b3+c3+6=2*3

a3+b3+c3+6=6

a3+b3+c3=0