Question

if a+b+c=2 and ab+bc+ca=2, then find a square+b square+c square. ​

Answer 1

ANSWER :

.: a² + b² + c² = 0

Step-by-step explanation:

${(a + b + c)}^{2} = { a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca$

${(a + b + c)}^{2} = { a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

${(2)}^{2} = { a}^{2} + {b}^{2} + {c}^{2} + 2(2)$

4 = a² + b² + c² + 4

.: a² + b² + c² = 4 -4

.: a² + b² + c² = 0