Question

if a+b+c=20 and ab+bc+ca= 75 find the value of a^3+b^3+c^3 - 3abc​

Answer 1

Answer:

Given: a+b+c=20, ab+nc+ca=75

As we know,

a³+b³+c³-3abc

=(a+b+c)(a²+b²+c²-2ab-2bc-2ca)

=20× {(a+b)²-2ab+c²-2(ab+bc+ca)}

=20{(a+b+c)²-2ab-2ac-2bc-2×75}

=20(400-150-150)

=20(400-300)

=20×100

=2000

2000 is the value of your given data.

Hope you understand.