Math, asked by kusumarangolis, 1 month ago

if a+b+c=270 then sin2a-sin2b+sin2c +4sinAsinBcosC=

Answers

Answered by MissVirius

Step-by-step explanation:

sin2A + sin 2B +sin2C = 2 sin(A+B)cos(A-B) + 2sinC cosC =2sinC cos(A-B)+2sinC cosC =2sinC (cos(A-b) + cos C) =2sin C(cos(A-B) - cos(A+B) ) = 2sinC . 2sin A sin B =4 sinA sin B sin C

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if a+b+c=270 then sin2a-sin2b+sin2c +4sinAsinBcosC=​

Answers

if a+b+c=270 then sin2a-sin2b+sin2c +4sinAsinBcosC=