If a + b + c = 29 and a 2 + b 2 + c 2 = 791, find ab + bc + ca
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(a + b + c) ²= a²+b²+c²+2(a+b+c)
(29)²=791+2(a+b+c). put the value of a + b + c
and a² + b² + c²
841 = 791+2(ab+bc+ac)
841 –791=2(ab+bc+ac)
50=2(ab+bc+ac)
ab+bc+ac = 50/2=25
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