Question

if a+b+c=2s, then find the value of (s-a)^3+(s-b)^3+3(s-a)(s-b)c​

Answer 1

Answer:

a=2

b=2

c=2

then

Step-by-step explanation:

(s-2)^3+ (s-2)^3+3(s-2)(s-2)2

now cancel all the s

so remains

2×3 + 2×3+3,+2+2+2

6+9+6

21

Ans is 21.