Math, asked by sunnyraj0204, 6 months ago

if a+b+c=2s then prove that (s-a) ²+ (s-b) ²+(s-c) ²=a²+b²+c²-s²

Answers

Answered by SIERRA7

Answer:

My frnd nothing in this world is free.If u are willing to receive good stuff u have to pay a high price first.I dont think anyone will do this whole sum just for 5 points.Pay us at least 50 to have a proper answer.Never expect people to give u things for free.Pay for them and earn them.Hope u understand my words

Answered by shreyasi414

Step-by-step explanation:

given:a+b+c=2s
LHS=(s-a)²+(s-b)²+(s-c)²
=s²+a²-2as+s²+b²-2bs+s²+c²-2cs
=3s²+a²+b²+c²-2s(a+b+c)
=3s²+a²+b²+c²-(2s*2s)
=a²+b²+c²-4s²+3s²
=a²+b²+c²-s²=RHS

Previous Question

Next Question

if a+b+c=2s then prove that (s-a) ²+ (s-b) ²+(s-c) ²=a²+b²+c²-s²​

Answers

if a+b+c=2s then prove that (s-a) ²+ (s-b) ²+(s-c) ²=a²+b²+c²-s²