Math, asked by sunnyraj0204, 5 months ago

if a+b+c=2s then prove that (s-a) ²+ (s-b) ²+(s-c) ²=a²+b²+c²-s²

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Answered by SIERRA7

Answer:

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Answered by shreyasi414

Step-by-step explanation:

given:a+b+c=2s
LHS=(s-a)²+(s-b)²+(s-c)²
=s²+a²-2as+s²+b²-2bs+s²+c²-2cs
=3s²+a²+b²+c²-2s(a+b+c)
=3s²+a²+b²+c²-(2s*2s)
=a²+b²+c²-4s²+3s²
=a²+b²+c²-s²=RHS

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if a+b+c=2s then prove that (s-a) ²+ (s-b) ²+(s-c) ²=a²+b²+c²-s²​

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if a+b+c=2s then prove that (s-a) ²+ (s-b) ²+(s-c) ²=a²+b²+c²-s²