If A+B+C=2s then prove that sin(S-A)+ sin(S-B)+sin C
Answers
Answered by
0
Answer:
ok
Step-by-step explanation:
Answered by
1
Answer:
please markm me
Step-by-step explanation:
Solution :
LHS
=sin(S-A)+sin(S-B)+sinC
=2sin(
2S-A-B
2
)⋅cos(
B-A
2
)+2sin(
C
2
)⋅cos(
C
2
)
=2sin(
C
2
)(cos(
B-A
2
)+cos(
C
2
))
=2sin(
C
2
)(2cos(
(
B-A
2
)+(
C
2
)
2
)⋅cos(
(
B
2
)-(
A
2
)-(
C
2
)
2
)
4sin(
C
2
)⋅cos(
B+C-A
4
)⋅cos(
B-A-C
4
)
4sin(
C
2
)⋅cos(
2S-2A
4
)⋅cos(
B-(2S-B)
4
)
4sin(
C
2
)⋅cos(
S-A
2
)⋅cos(
B-S
2
)
4cos(
S-A
2
)⋅cos(
S-B
2
)⋅sin(
C
2
).
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