If a + b + c = 2s then the value of (s - a)² + (s + b)² + (s - c)² will be ?
Answers
Answered by
15
hi,
if a+b+c=2s
then the value of
(s-a)²+(s+b)²+(s-c)²=(3s-2s)²
=(s)²
thanks..hope it helps
if a+b+c=2s
then the value of
(s-a)²+(s+b)²+(s-c)²=(3s-2s)²
=(s)²
thanks..hope it helps
Answered by
6
Answer:
Value of (s-a)²+(s-b)²+(s-c)² = -s²
Step-by-step explanation:
/*I think there is an error in the question.
It may be (s-a)²+(s-b)²+(s-c)² */
Given a+b+c= 2s---(1)
Now,
Value of (s-a)²+(s-b)²+(s-c)²
= s²-2sa+a²+s²-2sb+b²
+s²-2sc+c²
/* By algebraic identity:
(x-y)² = x²-2xy+y² */
= 3s² -2s(a+b+c)
= 3s² - 2s × 2s /* From (1) */
= 3s² - 4s²
= -s²
•••♪
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