Question

If a + b + C = 2s, then what will be the value of [(s–a)2 + (s–b)2 + (s–c)2 + s2] =?

Answer 1

Answer:

It may be (s-a)2+(s-b)2+(s-c)2 */

Given a+b+c=2---(1)

Now

value of (s-a)2+(s-b)2+(s-c)2

= s2 -2sa+a2+s2-2sb+b2 +s2-2sc+c2