If A+B+C =2W, cos²W + cos²(W - A) + cos²(W – B) + cos²(W-C)
= 2 + 2 cos A cos B cos C.
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We write cos2A=1−sin2A
and as in ΔABC A+B+C=180
⟹cosC=cos(180−A−B)=−cos(A+B)
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