if a+b+c=3 and a^2+b^2+c^2=6 and 1/a+1/b+1/c=1 then abc is?
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hello!!..
a+b+c=3. (1)
a²+b²+c²=6. (2)
1/a+1/b+1/c=1 (3)
abc=??
a+b+c=3 [Squaring both sides]
a²+b²+c²+2ab+2bc+2ca = 9
6+2(ab+bc+ca) = 9
(ab+bc+ca) = 3/2
bc+ac+ab=abc [using equation 3]
abc=3/2
a+b+c=3. (1)
a²+b²+c²=6. (2)
1/a+1/b+1/c=1 (3)
abc=??
a+b+c=3 [Squaring both sides]
a²+b²+c²+2ab+2bc+2ca = 9
6+2(ab+bc+ca) = 9
(ab+bc+ca) = 3/2
bc+ac+ab=abc [using equation 3]
abc=3/2
Antihero10SK:
just correct your answer to 32/9
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