Math, asked by bitulvermaapple, 5 months ago

If a-b-c=3 and a2+b2+c2=77 to find ab-bc+CA

Answers

Answered by ItzDinu
3

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a - b - c = 3

a² + b² + c² = 77

( a + (-b) + (-c)² = a²+b²+c²-2ab+2bc-2ca

9 = 77-2(ab-bc+ca)-(ab-bc+ca) = -34

=> ( ab - bc + ca ) = 34

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