If a-b-c=3 and a2+b2+c2=77 to find ab-bc+CA
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a - b - c = 3
a² + b² + c² = 77
( a + (-b) + (-c)² = a²+b²+c²-2ab+2bc-2ca
9 = 77-2(ab-bc+ca)-(ab-bc+ca) = -34
=> ( ab - bc + ca ) = 34
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