Math, asked by satbirdarria, 1 day ago

If a×b×c= 36, b×c×d= 48, c×d×a=324, d×b×a= 18, then find a×b×c×d=?

Answers

Answered by aaminathamiz
1

Step-by-step explanation:

abc = 36 …(1)

bcd = 48 …(2)

cda = 324 …(3)

dab = 18 …(4)

Multiply all the 4 equations to get

a^3xb^3xc^3xd^3 = 36x48x324x18

So abcd = [36x48x324x18]^(1/3) = 216

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